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Re: Rearrangement of a sequence into random order

• To: mathgroup at smc.vnet.net
• Subject: [mg28437] Re: [mg28434] Rearrangement of a sequence into random order
• From: maarten.vanderburgt at icos.be
• Date: Thu, 19 Apr 2001 03:26:25 -0400 (EDT)
• Sender: owner-wri-mathgroup at wolfram.com

Loren,

Try the following:

<<DiscreteMath`Permutations`\
n = 20;
RandomPermutation[20]

I think this does what you want.


Maarten van der Burgt

Leuven

Belgium





"Loren Dill" <lorendill at mediaone.net> on 18-04-2001 09:23:38 AM

cc:

Subject: [mg28437]  [mg28434] Rearrangement of a sequence into random order


Hi,

I'm a math teacher, and need to prepare exams from time to time.  I
typically prepare questions for the exam in a sequential order starting at
the beginning of the material and going to the end.  I may have something
like 20 short-answer questions.  I want a program that will randomize the
order of the questions.  In other words, I want to provide n, the number of
questions, and have the program provide a list of length n that contains
all
the numbers from 1 to n in a random order without any number being repeated
or omitted.  I'm sure that this is an easy task for Mathematica, but I
can't
figure out the best way to do it.

Loren Dill