Re: Rearrangement of a sequence into random order

*To*: mathgroup at smc.vnet.net*Subject*: [mg28437] Re: [mg28434] Rearrangement of a sequence into random order*From*: maarten.vanderburgt at icos.be*Date*: Thu, 19 Apr 2001 03:26:25 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Loren, Try the following: <<DiscreteMath`Permutations`\ n = 20; RandomPermutation[20] I think this does what you want. Maarten van der Burgt Leuven Belgium "Loren Dill" <lorendill at mediaone.net> on 18-04-2001 09:23:38 AM cc: Subject: [mg28437] [mg28434] Rearrangement of a sequence into random order Hi, I'm a math teacher, and need to prepare exams from time to time. I typically prepare questions for the exam in a sequential order starting at the beginning of the material and going to the end. I may have something like 20 short-answer questions. I want a program that will randomize the order of the questions. In other words, I want to provide n, the number of questions, and have the program provide a list of length n that contains all the numbers from 1 to n in a random order without any number being repeated or omitted. I'm sure that this is an easy task for Mathematica, but I can't figure out the best way to do it. Loren Dill