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Re: Pattern matching "on the fly"

  • To: mathgroup at smc.vnet.net
  • Subject: [mg30261] Re: Pattern matching "on the fly"
  • From: "Allan Hayes" <hay at haystack.demon.co.uk>
  • Date: Sat, 4 Aug 2001 01:14:28 -0400 (EDT)
  • References: <9jtk77$87r$1@smc.vnet.net> <9jvrbe$doi$1@smc.vnet.net> <9kdbfr$f2m$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Stephen,
My result was with

Version: "4.1 for Microsoft Windows (November 2, 2000)"
System: Windows 98
Machine: Toshiba Tecra 750 DVD


Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565



--
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565

"Stephen P Luttrell" <luttrell at signal.dra.hmg.gb> wrote in message
news:9kdbfr$f2m$1 at smc.vnet.net...
>
> "Allan Hayes" <hay at haystack.demon.co.uk> wrote in message
> news:9jvrbe$doi$1 at smc.vnet.net...
> > Tony,
> > Not a general solution, but for your example we get
> >
> >
> > (1+x)^1000000 +O[x]^3//Normal//Timing
> >
> > {0.27*Second, 1 + 1000000*x + 499999500000*x^2}
>
>
> and I got this result using Mathematica 4.1 (Windows NT 4):
>
> (1+x)^1000000 +O[x]^3//Normal//Timing
>
> {0.Second, 1 + 1000000000000000000000 x +
>       499999999999999999999500000000000000000000 x^2}
>
>
> --
> Stephen P Luttrell
> QinetiQ, Malvern, U.K.
> luttrell at signal.dera.gov.uk
> 01684-894046 (phone), 01684-894384 (fax)
>
>
>




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