Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2001
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2001

[Date Index] [Thread Index] [Author Index]

Search the Archive

using findroot for multiple functions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg30337] using findroot for multiple functions
  • From: Amy Sommer <amsommer at pacific.mps.ohio-state.edu>
  • Date: Sat, 11 Aug 2001 03:39:58 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

I need to solve multiple equations varying one parameter.  I am able to do
this if I vary the parameter in equal steps, but I have a list of numbers
that I need to plug in.  Here is an example because my description
probably is not very clear:

Here is an example of what works:

Table[t /.FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a], {t,0}],[a,1,10,.5]

My problem comes in because I want have a list of values that are not in
equal steps.  I have tried the following with no success:

list = {1, 3.4, 99.1,100,109}
ReplaceAll[[FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a],{t,0}],a-> list]

If anyone has an idea on how I can get this to work, please let me know.

Thanks,
Amy Sommer



  • Prev by Date: Re: Notebook Filename
  • Next by Date: Re: Adding text at various X,Y locations on Multi-Function Graphs
  • Previous by thread: Re: Expanding Trig Power Identities
  • Next by thread: Re: using findroot for multiple functions