Re: using findroot for multiple functions
- To: mathgroup at smc.vnet.net
- Subject: [mg30369] Re: [mg30337] using findroot for multiple functions
- From: BobHanlon at aol.com
- Date: Sun, 12 Aug 2001 02:29:58 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
In a message dated 2001/8/11 4:03:39 AM, amsommer at pacific.mps.ohio-state.edu
writes:
>I need to solve multiple equations varying one parameter. I am able to
>do
>this if I vary the parameter in equal steps, but I have a list of numbers
>that I need to plug in. Here is an example because my description
>probably is not very clear:
>
>Here is an example of what works:
>
>Table[t /.FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a], {t,0}],[a,1,10,.5]
>
>My problem comes in because I want have a list of values that are not in
>equal steps. I have tried the following with no success:
>
>list = {1, 3.4, 99.1,100,109}
>ReplaceAll[[FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a],{t,0}],a-> list]
>
>If anyone has an idea on how I can get this to work, please let me know.
>
list = {1, 3.4, 99.1,100,109};
FindRoot[(t-#)*Sin[t+#] + Sin[t-#]*Cos[t+#], {t,0}]& /@ list
{{t -> 0.9999999957859541},
{t -> -0.14754829012037235},
{t -> 7.717139365543081},
{t -> 0.5397879298427968},
{t -> 0.9469935794800659}}
Bob Hanlon
Chantilly, VA USA