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RE: Re: NIntegrate and Plot
*To*: mathgroup at smc.vnet.net
*Subject*: [mg30442] RE: [mg30430] Re: [mg30408] NIntegrate and Plot
*From*: "David Park" <djmp at earthlink.net>
*Date*: Sun, 19 Aug 2001 02:01:36 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
I think this might be a faster method for making the plots. Use NDSolve to
create an InterpolatingFunction for the plotted function.
f[x_, n_:2, betaN_:121.643] := Sech[betaN*x^n]^2;
Clear[F];
F[x_] = F[x] /. NDSolve[{Derivative[1][F][x] == f[x],
F[-0.4] == 0}, F, {x, -0.4, 0.4}][[1,1]]
InterpolatingFunction[{{-0.4, 0.4}}, "<>"][x]
Plot[F[x],
{x, -0.4, 0.4},
PlotStyle -> RGBColor[1, 0, 0]];
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
> From: BobHanlon at aol.com [mailto:BobHanlon at aol.com]
To: mathgroup at smc.vnet.net
>
>
> In a message dated 2001/8/17 3:45:32 AM, y.tesiram at pgrad.unimelb.edu.au
> writes:
>
> >I would like to plot the integral of,
> >
> >(Sech[betaN * x^n])^2 ,
> >
> >where beatN=121.643 and n=2 say. I have started by making a table of x
> >values as
> >
> >np=100;
> >x1 = Table[(-0.5 + ((i -1)/(np-1)), {i,1,np}];
> >x2 = t1^n;
> >x3 = (Sech[betaN * x^n])^2;
> >
> >I have tried NIntegrate but of course that just returns the total area
> >of
> >x3.
> >
>
> f[x_, n_:2, betaN_:121.643] := Sech[betaN*x^n]^2;
>
> Plot[f[x], {x, -0.5, 0.5},
> PlotRange -> All,
> PlotStyle -> RGBColor[0, 0, 1]];
>
> Plot[NIntegrate[f[t], {t, -0.5, x}],
> {x, -0.5, 0.5},
> PlotStyle -> RGBColor[1, 0, 0]];
>
> To combine these plots into one, you would probably want to use separate
> scales for the curves. See:
>
> http://support.wolfram.com/Graphics/Axes/TwoAxisGraph.html
>
>
> Bob Hanlon
> Chantilly, VA USA
>
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