Re: Very simple limit, why doesn't it evaluate?

*To*: mathgroup at smc.vnet.net*Subject*: [mg31924] Re: Very simple limit, why doesn't it evaluate?*From*: "Allan Hayes" <hay at haystack.demon.co.uk>*Date*: Wed, 12 Dec 2001 04:14:06 -0500 (EST)*References*: <9v49pp$n1v$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Jacek, We can extend the Limit function by using one of the standard packages that come with Mathematica. Load the package <<Calculus`Limit` Now we get Limit[4^(n+3)/(3^(n+4)-5),n->Infinity+I] Infinity -- Allan --------------------- Allan Hayes Mathematica Training and Consulting Leicester UK www.haystack.demon.co.uk hay at haystack.demon.co.uk Voice: +44 (0)116 271 4198 Fax: +44 (0)870 164 0565 "Jacek Dziedzic" <dust-NOSPAM- at tenbit.pl> wrote in message news:9v49pp$n1v$1 at smc.vnet.net... > It stunned me that the Mathematica 3.0 returns this very simple limit > unevaluated: > 4^(n+3)/(3^(n+4)-5), with n -> infinity. > > Moreover, the NLimit function returns 1.0756... which is a rather poor > approximation of infinity (the expected result)... Well I can understand > that NLimit is numerical and can't be relied on, but why does the original > Limit[] die on that? Or am I doing anything wrong? > > - Jacek Dziedzic > > >