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Re: Very simple limit, why doesn't it evaluate?


Jacek,

We can extend the Limit function by using one of the standard packages that
come with Mathematica.
Load the package

    <<Calculus`Limit`

Now we get

    Limit[4^(n+3)/(3^(n+4)-5),n->Infinity+I]


        Infinity

--
Allan

---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565


"Jacek Dziedzic" <dust-NOSPAM- at tenbit.pl> wrote in message
news:9v49pp$n1v$1 at smc.vnet.net...
> It stunned me that the Mathematica 3.0 returns this very simple limit
> unevaluated:
> 4^(n+3)/(3^(n+4)-5), with n -> infinity.
>
> Moreover, the NLimit function returns 1.0756... which is a rather poor
> approximation of infinity (the expected result)... Well I can understand
> that NLimit is numerical and can't be relied on, but why does the original
> Limit[] die on that? Or am I doing anything wrong?
>
> - Jacek Dziedzic
>
>
>




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