RE: Functions with Options

*To*: mathgroup at smc.vnet.net*Subject*: [mg31990] RE: [mg31984] Functions with Options*From*: "David Park" <djmp at earthlink.net>*Date*: Sat, 15 Dec 2001 01:30:09 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

You almost got it. Use newPlot[f_, {x_, min_, max_}, opts___?OptionQ] := Plot[f, {x, min, max}, opts] The difference is that opts has 3 underscores after it instead of 2. Two underscores means 1 or more arguments. Three underscores mean 0 or more arguments. The ?OptionQ is just an added check that makes sure it is a sequence of rules. David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ > From: guillerm at usal.es [mailto:guillerm at usal.es] To: mathgroup at smc.vnet.net > > [Please moderator, delete my previouos E mail] > > I would like build functions with Options using Mathematica > build-up functions > with the same options. > > Here is a naïf example: > > newPlot[f_, {x_, min_, max_}, opts__] := Plot[f, {x, min, max}, opts] > > If I use this function given options the solution is OK. i.e: > > newPlot[Sin[x], {x, 0 , 2 Pi}, PlotRange -> All] > > but, of course, it doen`t work if it not included options. i.e: > > In[]:= newPlot[Sin[x], {x, 0 , 2 Pi}] > > Out[]:= newPlot[Sin[x], {x, 0, 2 Pi}] > > How it should be made the function in the way that it works given > or not given > values for options. > > Thanks >