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Re: Appending to Lists
*To*: mathgroup at smc.vnet.net
*Subject*: [mg27057] Re: [mg27045] Appending to Lists
*From*: BobHanlon at aol.com
*Date*: Sat, 3 Feb 2001 04:58:53 -0500 (EST)
*Sender*: owner-wri-mathgroup at wolfram.com
b = {0.2, 0.6, 1.2, -0.2, 0.5, 0.3, 0.7, -0.2, -0.6};
c = {1, 2, 3, 1, 2, 1, 2, 1, 1};
a = (Split[Ordering[c], c[[#1]] == c[[#2]]&] /.
n_Integer :> b[[n]])
{{0.2, 0.3, -0.2, -0.2, -0.6}, {0.6, 0.5, 0.7}, {1.2}}
PadRight[#, Max[Length /@ a]]& /@ a
{{0.2, 0.3, -0.2, -0.2, -0.6}, {0.6, 0.5, 0.7, 0, 0},
{1.2, 0, 0, 0, 0}}
Bob Hanlon
In a message dated 2001/2/1 3:41:34 AM, j.k.jones at dl.ac.uk writes:
>I have a function that creates a list (a) from another list (b). The list
>elements are re-grouped in the new list according to a third list (c).
>A
>Position command is applied to list (c) for an element, then with this
>output the list (a) is created from list (b) at positions given by the
>element position data, list (c). This is repeated for the large number
>of
>elements in the original lists.
>The Position command is necessary as different elements appear in the list
>a
>different number of times.
>However, with the large number of elements in the lists (approx 50,000
>for a
>simple list), this method is _very_ slow.
>If any one can give me help in speeding this process up I would be very
>grateful.
>
>The data sets would look like this
>
> b c
>
> 0.2 1
> 0.6 2
> 1.2 3
> -0.2 1
> 0.5 2
> 0.3 1
> 0.7 2
> -0.2 1
> -0.6 1
>
>A List would then be created from this data ( the list (a) ) containing
>vectors for 1, 2 and 3. The data in (b) is not important, and the order
>in
>which elements in (c) drop out is not set.
>In this case the (a) list should look like
>
>a = { { 0.2, -0.2, -0.2, -0.6} , {0.6, 0.5, 0.7} , { 1.2 } }
>
>My current function looks like this
>
>Do[AppendTo[xfinal,
> Flatten[Part[X, #] & /@
> Position[Global`PARTICLE, i]]], {i, 1,
> Max[PARTICLE]}];
>
>where xfinal is an (a) list, i.e. to be created.
> X is the (b) list , i.e. to be addressed, and
> PARTICLE is the (c) list. It is referenced by number.
>
>and it is very slow!
>
>Also, after producing this list, the different vector elements need to
>be
>made the same length, and so 0.0 are added to the ends of all vector
>elements shorter than the longest. My current function for doing this looks
>like
>
>table = Table[0.0, {Length[First[long]]}]; Print["Table Created!"];
>
>Do[If[Length[Part[xfinal, i]] < Length[First[long]],
> AppendTo[Part[xfinal, i],
> Drop[table, (Length[Part[xfinal, i]])] ]], {i, 2,
> Length[xfinal]}];
>
>where list (long) just sorts the list elements according to length.
>
>This function is also very slow, and I was wondering, again, if anyone
>knew
>a faster way of implementing this. Is the production of a table, once,
>and
>then dropping bits off and appending the fastest method? Of course this
>needs to be done tens of thousands of times per set of data so any small
>speed increase would be very helpful ;->
>
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