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MathGroup Archive 2001

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RotateShape[Cuboid...

  • To: mathgroup at smc.vnet.net
  • Subject: [mg27220] RotateShape[Cuboid...
  • From: roelb at club-internet.fr (roelb)
  • Date: Mon, 12 Feb 2001 03:20:58 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,
On Mathematica3 for mac, the following input produces 2 rods crossing
with a 90° angle, as expected. That's OK.

Show[Graphics3D[Cylinder[.3,1,10] ],RotateShape[
         Graphics3D[Cylinder[.3,1,10 ] ],
                  0,Pi/2,0]]

But a quite similar RotateSphape input applied to Cuboids doesn't behave
in the same manner. Why? (I expected the top Cudoid being oriented
differently than the botton one).

Show[Graphics3D[Cuboid[{-1,-1,0},{1,1,1}]] ,
  RotateShape[Graphics3D[Cuboid[{-1,-1,1},{1,1,2}]],
                 0,1,0]]

The mathematica book state that cuboids faces are parallel to the axes.
Should it means that RotateShape doesn't apply?



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