RotateShape[Cuboid...
- To: mathgroup at smc.vnet.net
- Subject: [mg27220] RotateShape[Cuboid...
- From: roelb at club-internet.fr (roelb)
- Date: Mon, 12 Feb 2001 03:20:58 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Hi,
On Mathematica3 for mac, the following input produces 2 rods crossing
with a 90° angle, as expected. That's OK.
Show[Graphics3D[Cylinder[.3,1,10] ],RotateShape[
Graphics3D[Cylinder[.3,1,10 ] ],
0,Pi/2,0]]
But a quite similar RotateSphape input applied to Cuboids doesn't behave
in the same manner. Why? (I expected the top Cudoid being oriented
differently than the botton one).
Show[Graphics3D[Cuboid[{-1,-1,0},{1,1,1}]] ,
RotateShape[Graphics3D[Cuboid[{-1,-1,1},{1,1,2}]],
0,1,0]]
The mathematica book state that cuboids faces are parallel to the axes.
Should it means that RotateShape doesn't apply?