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Re: How to define a polyfunction?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg27421] Re: How to define a polyfunction?
  • From: "Allan Hayes" <hay at haystack.demon.co.uk>
  • Date: Sun, 25 Feb 2001 00:53:48 -0500 (EST)
  • References: <974vp8$6jh@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Liwen,
You get,

golf=t^2-t;

Key[t_]:=If[(D[golf[t],t]>0),(t^4+t*3),(t^2.5-t)];

Key[2]

General::ivar: 2 is not a valid variable.

If[D[(-t + t^2)[2], 2] > 0, 2^4 + 2*3, 2^2.5 - 2]

Two problems:
a)  2  is passed to the right giving  D[golf[2],2], which makes no sense
b) golf is not a function, so even golf[2]] would not work as you would like
We also need to consider the possible effect of an of  t having a value when
golf and Key are defined or when Key is used.

golf[2]

\!\(\((\(-t\) + t\^2)\)[2]\)

Some suggestions

Following b)

Define a function golf; use its derivative, golf', use SetDelayed, :=,

Clear["`*"]
t=3;
golf[t_]:=t^2-t;
Key[t_]:=If[(golf'[t]>0),(t^4+t*3),(t^2.5-t)];
Key[2]

        22

Following a)
Separate the two roles of t; use SetDelayed and Block

Clear["`*"]
t=3;
golf:=t^2-t;
Key[s_]:=
  Block[{t},
    If[(D[golf,t]/.t\[Rule]s )>0,(s^4+s*3),(s^2.5-s)]
    ];
Key[2]

        22

Similarly

Clear["`*"]
t=3;
golf:=t^2-t;
Key[s_]:=
  Block[{t},
    If[D[golf,t]>0,(#^4+#*3),(#^2.5-#)]&[s]
    ]
Key[2]

        22

and thirdly,

Clear["`*"]
t=3;
golf:=t^2-t;
Key[s_]:= Block[{ t=s},
    Block[{t},
      If[D[golf,t]>0,(s^4+s*3),(s^2.5-s)]
      ]
    ];
Key[2]

        22

--
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565

"liwen liwen" <gzgear at yahoo.com> wrote in message
news:974vp8$6jh at smc.vnet.net...
> Dear friend,
>          How are you!Now I encounter a problem that I
> can not solve for a long time .
> It can be express simplely as how to define a
> polyfunction,for example,a simple polyfunction may be
> defined as that:
>
> Key[t_]:=If[(t>0),1,0];
>
> It is easy to define.However,it will be more difficult
> when the condition turns more complicate.For instance:
> golf=t^2-t;
> Key[t_]:=If[(D[golf[t],t]>0),(t^4+t*3),(t^2.5-t)];
>
>
> Best regards,
>
>
> Liwen
> E-mail:  gzgear at yahoo.com
>
> __________________________________________________
> Do You Yahoo!?
> Yahoo! Auctions - Buy the things you want at great prices!
http://auctions.yahoo.com/
>




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