Re: Deriviation d/dt(x(t))
- To: mathgroup at smc.vnet.net
- Subject: [mg27442] Re: [mg27407] Deriviation d/dt(x(t))
- From: BobHanlon at aol.com
- Date: Sun, 25 Feb 2001 20:55:46 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Dt[x^2 + y^2 == r^2, t, Constants -> {r}]
2*x*Dt[x, t, Constants -> {r}] +
2*y*Dt[y, t, Constants -> {r}] == 0
or
Dt[x^2 + y^2 == r^2, t] /. Dt[r, t] -> 0
2*x*Dt[x, t] + 2*y*Dt[y, t] == 0
or
D[x[t]^2 + y[t]^2 == r^2, t]
2*x[t]*Derivative[1][x][t] + 2*y[t]*Derivative[1][y][t] == 0
Bob Hanlon
In a message dated 2001/2/25 1:14:25 AM, maier1 at sbox.tu-graz.ac.at writes:
>I have a problem, having a definition of a circle: x^2+y^2=r^2
>Where x and y are functions of the time: x(t), y(t) and r ist a constant.
>
>Now I want to deriviate the equation to get the velocity vector.
>It should be : 2 x dx/dt +2 y dy/dt = 0
>
>Can anyone tell me how to do?
>