Re: converting hex strings

*To*: mathgroup at smc.vnet.net*Subject*: [mg27434] Re: converting hex strings*From*: "Paul Lutus" <nospam at nosite.com>*Date*: Sun, 25 Feb 2001 20:55:37 -0500 (EST)*References*: <97a7b2$aks@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

<maarten.vanderburgt at icos.be> wrote in message news:97a7b2$aks at smc.vnet.net... > Hallo, > > I have a list of hexadecimal strings (read from a hex string text file): > e.g. {"01a0", "fffe", "0080"} representing integers. > How can I convert such a list to integers so that I get {416, 4094, 128}? > I cannot make a function using something like > > hextoint = 16^^#& > > or > > hextoin = 16^^ToExpression[#]& > > I get errors like below: > > In[44]:= hexstr = "a1b0" > t = ToExpression[hexstr]; > 16^^t > General::"digit": "Digit at position \!\(1\) in \!\(\"t\"\) is too large to > \ > be used in base \!\(16\)." > > Where does this error come from? > > While this works ok: > In[43]:= 16^^a1b0 > Out[43]= 41392 > > The ToExpression[ ] also would give problems: ToExpression["01a0"] returns > 0. > > Has anyone done anything along these lines? I think this will do it for you: myhex[x_String] := Module[ {str}, str = StringJoin["16^^",x]; ToExpression[str] ]; data = {"01a0","fffe","0080"}; Map[myhex,data] {416,65534,128} > How would I have to convert a hex list representing floats (IEEE floating > point standard)?, e.g. {"42c8000", "3dfcd35b", "bf80000"} which should > convert to {100.0, 0.12345, -1.0} in a decimal notation. I think that will be much more difficult -- it will require a full grasp of the IEEE specification within the converter code. -- Paul Lutus www.arachnoid.com