Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2001
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2001

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Integration by substitution

  • To: mathgroup at smc.vnet.net
  • Subject: [mg29821] Re: Integration by substitution
  • From: Ignacio Rodriguez <ignacio at sgirmn.pluri.ucm.es>
  • Date: Thu, 12 Jul 2001 02:52:34 -0400 (EDT)
  • Organization: UCM
  • References: <9ig788$kh5$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

In my case (Mathematica 3.0) none of them are answered.

"G. A. Garrett" wrote:

> I was wondering if someone could explain to me why the first input
> below gives no answer while the second input does. It never crossed my
> mind the Mathematica wouldn't have seen the simple substitution of
> sp=s/a that produced an answer. I am running ver. 4.0 in a Windows
> environment. I am basically looking for a characteristic that I can be
> on the look out for in the future.
>
> Integrate[Sech[s/a]^2 Sech[(t - s)/a]^2, {s, -Infinity, Infinity}]
>
> Integrate[a Sech[sp]^2 Sech[(tp - sp)]^2, {sp, -Infinity, Infinity}]
>
> Gregory
> --Posted email rarely checked--

--

Ignacio Rodriguez Ramirez de Arellano
Unidad de RMN
Universidad Complutense
Paseo Juan XXIII, 1
Madrid 28040, Spain

Tel. 34-91-394-3288
Fax  34-91-394-3245
e-mail: ignacio at sgirmn.pluri.ucm.es





  • Prev by Date: Comparison of Mathematica on Various Computers
  • Next by Date: Re: Integration by substitution
  • Previous by thread: Re: Integration by substitution
  • Next by thread: Re: Integration by substitution