Re: convert an expression to an infinite series
- To: mathgroup at smc.vnet.net
- Subject: [mg29632] Re: [mg29618] convert an expression to an infinite series
- From: Andrzej Kozlowski <andrzej at tuins.ac.jp>
- Date: Fri, 29 Jun 2001 01:36:05 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
on 01.6.28 6:28 PM, Toshiyuki (Toshi) Meshii at meshii at mech.fukui-u.ac.jp
wrote:
> Hello,
>
> Does anyone know a way to convert an expression to an infinite series?
> Let me show the idea by a concrete problem.
>
> In[29]:=
> Sum[E^(-2*m*n*L), {n, 0, Infinity}]
>
> Out[29]=
> E^(2*L*m)/(-1 + E^(2*L*m))
>
> Yes, Mathematica 4.1 knows that the infinite sum converges to a specific
> value.
> Then, my question is that how can I expand the expression
> E^(2*L*m)/(-1 + E^(2*L*m))
> in an infinite series on n, in this case
> Sum[E^(-2*m*n*L), {n, 0, Infinity}]
>
> Is there any way or is it an one way path?
>
> -Toshi
>
>
>
>
First of all, if Mathematica returned Sum[E^(-2*m*n*L), {n, 0, Infinity}]
than it would of course immediately evaluate it back to E^(2*L*m)/(-1 +
E^(2*L*m)) and you would be back where you started. That of course could be
dealt with by using HoldForm (for example). Secondly, it would be extremely
difficult (perhaps impossible) to implement what you want in sufficient
generality for it to be useful. (I take that you would like Mathematica to
return a power-series in terms of a general "n-th term". One can certainly
implement a limited version of this and there may be a package that does it
but the following method is actually more useful. (Copy the expression
below the signature and paste into a Mathematica notebook).
--
Andrzej Kozlowski
Toyama International University
JAPAN
http://platon.c.u-tokyo.ac.jp/andrzej/
http://sigma.tuins.ac.jp/~andrzej/
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