MathGroup Archive 2001

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log x > x - proof?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg28049] log x > x - proof?
  • From: "Joe" <sorry at no.email>
  • Date: Thu, 29 Mar 2001 03:24:14 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Dear all,

Please could someone give me some hints as to how to prove that

log x > x for all x > 0

Isn't it proof by contradiction, or by intimidation?

Thanks in advance,

Joe




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