log x > x - proof?
- To: mathgroup at smc.vnet.net
- Subject: [mg28049] log x > x - proof?
- From: "Joe" <sorry at no.email>
- Date: Thu, 29 Mar 2001 03:24:14 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Dear all, Please could someone give me some hints as to how to prove that log x > x for all x > 0 Isn't it proof by contradiction, or by intimidation? Thanks in advance, Joe