AW: Exponential Equations

*To*: mathgroup at smc.vnet.net*Subject*: [mg28832] AW: [mg28792] Exponential Equations*From*: Matthias.Bode at oppenheim.de*Date*: Tue, 15 May 2001 00:59:03 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Phil, IN: Solve[3^(2 x) == (1/9)^(x + 5), x]; N[%] OUT: Solve::"ifun": "Inverse functions are being used by \!\(Solve\), so some \ solutions may not be found." {{x -> -2.5 + 1.4298 \[ImaginaryI]}, {x -> -2.5 - 1.4298 \[ImaginaryI]}, {x -> -2.5 - 2.8596 \[ImaginaryI]}, {x -> -2.5}} The last result appears to be the one you expected. Sincerely, Matthias Bode Sal. Oppenheim jr. & Cie. KGaA Koenigsberger Strasse 29 D-60487 Frankfurt am Main GERMANY Tel.: +49(0)69 71 34 53 80 Mobile: +49(0)172 6 74 95 77 Fax: +49(0)69 71 34 6380 E-mail: matthias.bode at oppenheim.de Internet: http://www.oppenheim.de "Why can't Mathematica find x = -5/2 when executing the following? Is there a package I should load? It seems so simple. Solve[3^(2 x)==(1/9)^(x + 5),x]"