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MathGroup Archive 2001

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Re: ListPlot vs ListPlot3D

  • To: mathgroup at smc.vnet.net
  • Subject: [mg28916] Re: ListPlot vs ListPlot3D
  • From: "Orestis Vantzos" <atelesforos at hotmail.com>
  • Date: Fri, 18 May 2001 01:13:20 -0400 (EDT)
  • Organization: National Technical University of Athens, Greece
  • References: <9e02ft$2vu@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Well, given that ListPlot3D creates surfaces (and not a line in 3D space) it
is definitely not so simple to extend its functionality in the way you
specify.
One could write a package though, that takes an array of points in 3D space
and creates a mesh of polygons (so that four adjacent points in the matrix
would define a polygon).
ListConvolve with the right arguments could do the trick, I think...
Orestis Vantzos


"Otto Linsuain" <linsuain+ at andrew.cmu.edu> wrote in message
news:9e02ft$2vu at smc.vnet.net...
>
> Dear Mathematica experts, I was wondering if there is a way of plotting
> a 3D graph using a rectangular array of z-values USING THE CORRESPONDING
> VALUES OF X AND Y.
>
> Here is what I mean:
>
> with a 2D plot, one can do:
>
> ListPlot[ {y1,y2,y3,.........yn} ]  and this will give a graph of the
points
>
> {y1,1} ,{y2,2}, {y3,3},....{yn,n}, i.e. it will use the integers
> 1,2,3,...n as the x values.
>
> One can, however, write
>
> ListPlot[ { {x1,y1}, {x2,y2}, {x3,y3}, ... {xn,yn} }]
>
> and get a graph with user-specified values for x and y.
>
> There doesn't seem to be an analogous thing for ListPlot3D. The values
> of x and y seem to be always {1,1}, {1,2},{2,1},{2,2},.......{n,n}
>
> Any ideas? Thanks in advance. Otto Linsuain.
>




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