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MathGroup Archive 2001

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Re: 2nd order differential equation help

  • To: mathgroup at smc.vnet.net
  • Subject: [mg31502] Re: 2nd order differential equation help
  • From: bghiggins at ucdavis.edu (Brian Higgins)
  • Date: Thu, 8 Nov 2001 04:55:09 -0500 (EST)
  • References: <9sb4rb$h1n$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Here is one way to do your problem:

eqn = g''[t] + 0.1g'[t] + g[t] == 0
sol = DSolve[{eqn, g[0] == 0, g'[0] == 1}, g[t], t]
Plot[g[t] /. sol, {t, 0, 10Pi}]

Cheers, 

Brian


news:<9sb4rb$h1n$1 at smc.vnet.net>...
> Exactly how do I get this into a form Mathamatica will accept?  It has
> been a number of years since enrolling in diffeq, however I think I am
> close to correct but would appreciate help.
> 
> the problem;
> 
> Solve the differential equation:
> 		
> g''(t) + 0.1 g'(t) + g(t) = 0 
> 
> where the previous equation uses conventional mathematical notation. 
> You must transfrom the equation and initial conditions into
> Mathematica syntax.
> 
> for t between 0 and 10 Pi
> 
> subject to the initial conditions
> 	g(0) = 0,
> 	g'(0) = 1
> 
> Plot your results.
> 		
> My attempt is as follows:
> 
> 
> Clear[g]
> 
> Clear[eqn]
> 
> eqn[t_] = g''[t] + 0.1g'[t] + g[t] == 0
> 
> 
> Clear[eqn1]
> 
> eqn1[t_] = g'[t] + 0.1g[t] + ?g[t] == 0
> 
> solution = DSolve[{eqn[t], eqn1[t]}, g'[0] == 1, 
> g[0] == 0, g[t], {t, 0, 10\[Pi]}]
> 
> DSolve::dsvar: g[0]==0 cannot be used as a variable.
> 
> what am I dont doing right?  any suggestions helpful


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