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MathGroup Archive 2002

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Re: Using rules from Solve

  • To: mathgroup at smc.vnet.net
  • Subject: [mg33697] Re: Using rules from Solve
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Tue, 9 Apr 2002 01:01:59 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <a8m2vj$oag$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

can you make postings without obvious syntax errors ?
and do you mean ReplaceAll[] instead of Replace[] ?

Regards
  Jens


postman wrote:
> 
> Hey All:
> I appreciate any help with the following. I have a working solution,
> but don't understand why my first attempt failed. I'm using Solve to
> generate solutions to a set of simultaneous equations (the mass action
> equations in chemistry), then want to use the resulting solutions to
> calculate numerical values for specific values of the parameters.
> 
> KdEqn={Kd==R*L/RL, RT=RL+R}
> 
> Solve[KdEqn,RL,{RF}] gives me a rule,
> 
> {{RL->L*RT/(Kd+L)}}
> 
> and Replace[RL,Flatten[Solve[KdEqn,RL,{RF}]]] gives an expression
> 
> L*RT/(Kd+L)
> 
> that looks like what I would type on the right hand side of a
> function:
> 
> Rl[L_] := L*RT/(Kd+L)
> 
> The problem is that
> 
> Rl[L_] := Replace[RL,Flatten[Solve[KdEqn,RP]{Rf}]]
> 
> fails; Rl[1] does not substitute the value "1" for "L". However,
> 
> Rl[L_] = Replace[RL,Flatten[Solve[KdEqn,RP]{Rf}]]
> 
> works as I want. Why does the := construct fail here?
> 
> Thanks for any help!


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