Re: Pattern matching
- To: mathgroup at smc.vnet.net
- Subject: [mg33961] Re: Pattern matching
- From: bghiggins at ucdavis.edu (Brian Higgins)
- Date: Wed, 24 Apr 2002 01:22:51 -0400 (EDT)
- References: <aa3fq4$7tv$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
John, Perhaps this will be more efficient: myfunc[data_, template_] := Flatten[Map[Function[w, Select[data, MatchQ[Characters[#], w] &]], Characters[template] /. "?" -> _]] In[30]:=myfunc[listData,listTemplates] Out[30]={400HGXX--,960KG1D--} Cheers, Brian John Leary <leary at paradise.net.nz> wrote in message news:<aa3fq4$7tv$1 at smc.vnet.net>... > Greetings > > Can you help me please - there must be a simple solution to this problem, > but I can't find it. > > From a list of character strings and a list of templates, I need to > produce a list of all strings that match any of the templates. For example: > > listData={"18K0F3C--" , "2K40GXX--" , "400HGXX--" , "5M00G1F--" , "960KG1D--"} > listTemplates={"???H?????" , "???K?????"} > result={"400HGXX--","960KG1D--"} > > In the templates, ? is a wild-card that represents a single character. > The data strings contain only alpha-numeric characters and hyphens - no > other characters. > There are no special requirements for the result: duplication and random > order are acceptable. > > > I searched the MathGroup archive and found a very useful function that does > exactly what I want, but it works only on individual strings, not lists of > strings (msg00051): > > QMMatchQ[s_String, p_String] := MatchQ[Characters[s], Characters[p] /. "?" > -> _ ] > > > > I tried to use it in the following way, but the result is a list of the > matching templates, not the matching strings : > > QMMatchQ[s_String, p_String] := MatchQ[Characters[s], Characters[p] /. "?" > -> _ ] > SetOptions[Intersection, SameTest -> (QMMatchQ[#1,#2]& )]; > result=Intersection[listData,listTemplates] > {"???H?????","???K?????"} > > > It ought to be a small step from there to the result that I need, but I > can't find a simple solution. > > One alternative approach would be a Do loop: > > b={}; > Do[b=Append[b,Select[listData,QMMatchQ[#,listTemplates[[n]]]&]],{n,1,Length[listTemplates]}] > > This works but seems to be very slow for large lists. In the real case, > listData can be very large - up to 250,000 elements - and the Do loop > approach doesn't seem to be optimum. > > > I would be very grateful for your help. > > > Regards > > John Leary