Re: Handling a list: Could you find a more elegant solution?
- To: mathgroup at smc.vnet.net
- Subject: [mg38240] Re: Handling a list: Could you find a more elegant solution?
- From: atelesforos at hotmail.com (Orestis Vantzos)
- Date: Tue, 10 Dec 2002 04:09:35 -0500 (EST)
- References: <asn36u$40k$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Listability of basic numerical operators is a major feature of Mathematica__use it!
Your target is equal to ({a,b,c,d}+{b,c,d,e})/2
So:
(Drop[list1,-1]+Drop[list1,1])/2
Also:
Drop[list1+RotateLeft[list1],-1]/2
Orestis
guillerm at usal.es wrote in message news:<asn36u$40k$1 at smc.vnet.net>...
> I have a list:
>
> list1 = {a, b, c, d, e};
>
> I want manipulate the list to obtain:
>
> (*Out[]:{(a + b)/2, (b + c)/2, (c + d)/2, (d + e)/2}*)
>
> It can be done for this function
>
> f[data_List] := Drop[Plus @@ NestList[RotateRight, data,
> 1], 1]/2
>
> f[list1]
>
> but I am sure that some member of the group can find a more elegant function. I
> will appreciate to know it.
>
> Thanks
>
> Guillermo Sanchez
>
>
> ---------------------------------------------
> This message was sent using Endymion MailMan.
> http://www.endymion.com/products/mailman/