RE: Question about precision.
- To: mathgroup at smc.vnet.net
- Subject: [mg38416] RE: [mg38405] Question about precision.
- From: "Florian Jaccard" <jaccardf at eicn.ch>
- Date: Sat, 14 Dec 2002 03:19:55 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Hello ! I'm not an expert... But here a easy way fo obtain 50 significant numbers : In[1]:= Sqrt[1.3`50] Out[1]= 1.14017542509913797913604902556675447907600531091641 In[2]:= % %//FullForm Out[2]//FullForm= 1.2999999999999999999999999999999999999999999999999999999999999694004`50 Meilleures salutations Florian Jaccard -----Message d'origine----- De : Wen-Feng Hsiao [mailto:wfhsiao at libra.seed.net.tw] Envoyé : ven., 13. décembre 2002 10:19 À : mathgroup at smc.vnet.net Objet : [mg38405] Question about precision. Dear experts, I try to find the square root of 1.3, but obtain an not so correct answer. Could someone point me how to do? My trials are the followings. In[28]:= Sqrt[1.3] Out[28]= 1.14018 In[29]:= Precision[Sqrt[1.3]] Out[29]= 16 In[30]:= N[Sqrt[1.3], 50] Out[30]= 1.14018 In[31]:= 1.14018*1.14018 Out[31]= 1.30001 The more precise answer should be In[32]:= 1.140175425*1.140175425 Out[32]= 1.3 Thanks for your help! Wen-Feng Hsiao