Re: Why can't Mathematica find this root?
- To: mathgroup at smc.vnet.net
- Subject: [mg38436] Re: Why can't Mathematica find this root?
- From: "David W. Cantrell" <DWCantrell at sigmaxi.org>
- Date: Sun, 15 Dec 2002 02:10:03 -0500 (EST)
- References: <at4dgq$f1c$1@smc.vnet.net> <at9b6n$pqk$1@smc.vnet.net> <200212130908.EAA03312@smc.vnet.net> <ateq76$92m$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Daniel Lichtblau <danl at wolfram.com> wrote: > I did not really understand at first the nature of the question. Now > that I do I'll take a stab at it. Under Solve>Further Examples>"Getting > infinite solution sets for some equations" in the Help Browser, there is > code to do something called "GeneralizeSolve". Many thanks for pointing this out. I had not see it before. It answers the question at the end of my previous post in this thread: "Can anyone suggest a simple way, avoiding human intervention, to have Mathematica give an equivalent form of the result?" > It is based on finding > periodic inverses to various known functions, and takes advantage of the > fact that Solve will find solutions in terms of these inverse functions. > It does not quite work directly on your problem for the simple reason > that e.g. ArcSin[0] will evaluate to 0. So we make it work by solving > f'[x]==a and substituting a->0 afterward. (Yes. I had suggested this also.) [snip of code,...] > A minor inconvenience is that some solutions may be listed more than > once e.g. the last two are equivalent if we regard n as ranging over all > integers. OTOH, instead of being viewed as an inconvenience, it might be regarded in some situations as providing valuable information about the multiplicities of the roots. David Cantrell -- -------------------- http://NewsReader.Com/ -------------------- Usenet Newsgroup Service New Rate! $9.95/Month 50GB
- References:
- Re: Why can't Mathematica find this root?
- From: "Konrad Den Ende" <konrad@voxway.com>
- Re: Why can't Mathematica find this root?