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Re: Question about precision.

  • To: mathgroup at smc.vnet.net
  • Subject: [mg38452] Re: Question about precision.
  • From: Nigel King <king at dircon.co.uk>
  • Date: Mon, 16 Dec 2002 02:20:43 -0500 (EST)
  • References: <atcasb$3m0$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

In <atcasb$3m0$1 at smc.vnet.net> Wen-Feng Hsiao wrote:
> I try to find the square root of 1.3, but obtain an not so correct
> answer. Could someone point me how to do? My trials are the
> followings.

In order to display a number to its full precision, it is often 
necessary to use NumberForm

In[1]:= NumberForm[Sqrt[1.3], 50] Out[1]//NumberForm= "1.
140175425099138"

An alternative is to specify the precision of 1.3 using 1.3`30

In[2]:=
Sqrt[1.3`30]
Out[2]=
1.140175425099137979136049025567

Note that the internally held answer for Sqrt[1.3] is much more accurate 
than the displayed number.

In[3]:=
x = Sqrt[1.3]
Out[3]=
1.14018

In[4]:=
NumberForm[x*x, 50]
Out[4]//NumberForm=
"1.3"

I hope this helps
---
Nigel


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