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MathGroup Archive 2002

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RE: Stumped again on a simple list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg32809] RE: [mg32795] Stumped again on a simple list
  • From: "Florian Jaccard" <jaccardf at eicn.ch>
  • Date: Thu, 14 Feb 2002 01:43:24 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Hello Rob !

I'm not sure to understand what you want to get.

Is it the following ?

ii=Table[z,{z,50,1400,5}];

In[2]:=
jj=Table[If[ii[[k]]<100,50,200],{k,1,Length[ii]}]

Meilleures salutations

Florian Jaccard
EICN-HES
e-mail : jaccardf at eicn.ch


-----Message d'origine-----
De : 1.156 [mailto:rob at piovere.com]
Envoyé : mar., 12. février 2002 12:24
À : mathgroup at smc.vnet.net
Objet : [mg32795] Stumped again on a simple list


Greetings cypherers all,

I make a simple list ii and I find I can make other lists easily by
algebraic moves like
jj=ii/2, etc.  But when I want make a new list which splits two different
formula, I'm stumped.

Here's a stripped down version to illustrate my problem.  I want to use the
value in the original
array to determine how to make the new array.  The If[] is the only thing I
can find to make
this decision.  But, it seems I'm not even close when I try:


ii=Table[z,{z,50,1400,5}];

jj=If[ii<100,50,200]

I've looked around a good bit but have not stumbled into any topic that
appears to bear on this problem.

Can I please ask a kind soul to (again) point me in the right direction?

Thanks, Rob





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