Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2002
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2002

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: A question of Fit

  • To: mathgroup at smc.vnet.net
  • Subject: [mg32208] Re: A question of Fit
  • From: "John Doty" <jpd at w-d.org>
  • Date: Sat, 5 Jan 2002 00:11:08 -0500 (EST)
  • References: <a13v0b$dfo$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

In article <a13v0b$dfo$1 at smc.vnet.net>, "none" <none at none.com> wrote:

> I'd like to fit data of two independent variables, similar to the
> typical
> 
> Fit[data, {1, x, y, TBD}, {x, y}]
> 
> (data of the form      {{x1, y1, z1}, {x2, y2, z2}, ..., {xn, yn,
>      )
> 
> I have enough knowledge of the data to state that
> 
> z [x, 0]  = = x
> 
> Is there a way to force a fitted function to pass through the known
> points at y = = 0?

Subtract x from z to make a new function w. Now w[x,0]==0. Choose as
your fit functions suitable functions equal to zero when y==0, like y,
y^2, x*y, Cos[x]*Sin[y], etc.


-- 
| John Doty		"You can't confuse me, that's my job."
| Home: jpd at w-d.org
| Work: jpd at space.mit.edu


  • Prev by Date: Re: 1 equals 3 (among others)
  • Next by Date: Re: Length and Drop
  • Previous by thread: A question of Fit
  • Next by thread: Re: A question of Fit