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MathGroup Archive 2002

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System Ax=b!

  • To: mathgroup at smc.vnet.net
  • Subject: [mg32224] System Ax=b!
  • From: Rebeka Renko <irc_rebecca at yahoo.com>
  • Date: Mon, 7 Jan 2002 03:16:55 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

Hi!

I would really be happy, if someone could help me.
I was trying to write a program in mathematica on how
to solve the system Ax=b with partial pivoting, where
A is a three-diagonal matrix(a matrix that only has
numbers on the main diagonal and on two diagonals that
are lying on both sides from that main diagonal, every
other element is 0), but came nowhere. 
That is why it would be nice if someone has any
suggestions how I could do that.
I am looking forward on your answer and am thanking
you in advance!

Regards

Rebeka



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