       Re: polar curve

• To: mathgroup at smc.vnet.net
• Subject: [mg32348] Re: polar curve
• From: "Borut L" <borut at email.si>
• Date: Wed, 16 Jan 2002 03:29:58 -0500 (EST)
• References: <a20mh4\$4h2\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Is this your homework assignment? Because it sounds like a homework
assignment.

Anyway, I am cool enough to give you few tips:

x(t) = r(t) cos(t)
y(t) = r(t) sin(t)

Derivate x(t) on t and you get x'(t), set this to zero, and you get yourself
x0, y0 follows.
Draw the curve (PolarPlot[r(t)] or ParametricPlot[{x[t],y[t]}]) and figure
out the nature of the tangents at those points.

<TeKkEnXpErT at aol.com> wrote in message news:a20mh4\$4h2\$1 at smc.vnet.net...
>
> A polar curve defined by the equation r = 4cos(theta) -pie/2<=theta<=pie/2
>
> Parametrize the curve by x(theta), y(theta). Find the points (x,y) on this
> curve at which x'(theta)=0. What can you say about the tangent at  these
> points?
>
>

```

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