Re: polar curve

*To*: mathgroup at smc.vnet.net*Subject*: [mg32348] Re: polar curve*From*: "Borut L" <borut at email.si>*Date*: Wed, 16 Jan 2002 03:29:58 -0500 (EST)*References*: <a20mh4$4h2$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Is this your homework assignment? Because it sounds like a homework assignment. Anyway, I am cool enough to give you few tips: x(t) = r(t) cos(t) y(t) = r(t) sin(t) Derivate x(t) on t and you get x'(t), set this to zero, and you get yourself x0, y0 follows. Draw the curve (PolarPlot[r(t)] or ParametricPlot[{x[t],y[t]}]) and figure out the nature of the tangents at those points. <TeKkEnXpErT at aol.com> wrote in message news:a20mh4$4h2$1 at smc.vnet.net... > > A polar curve defined by the equation r = 4cos(theta) -pie/2<=theta<=pie/2 > > Parametrize the curve by x(theta), y(theta). Find the points (x,y) on this > curve at which x'(theta)=0. What can you say about the tangent at these > points? > >