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Re: Simple Trigonometric Integrals
*To*: mathgroup at smc.vnet.net
*Subject*: [mg32359] Re: [mg32338] Simple Trigonometric Integrals
*From*: Richard Gass <gass at physics.uc.edu>
*Date*: Wed, 16 Jan 2002 03:30:15 -0500 (EST)
*References*: <200201150730.CAA04585@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Joe,
In my experience when you have an expression that is a long sum of
terms you can often get dramatic speedups by mapping integrate across
the expression. On my machine a 500Hz G4 your integral takes 0.1
second this way.
Joe = a c Cos[t]/(g s) + b q Cos[2 t]/(c f) + c Cos[3 t]/(d a) +
d f Cos[4 t]/(h a n) + e q Cos[5t]/(g a) + f l Cos[6 t]/(w r m) +
g b Cos[7 t]/(o n x) + h Sin[t]/(b c) + i Sin[2 t]/(h e r) +
j y Sin[3 t]/(l p) + d k Sin[4 t]/(j c) + l m a Sin[5 t]/(f s b h)
+m p Sin[6 t]/(k j) + q n Sin[7 t]/(x c)
In[274]:=
Map[Integrate[#,{t,0,2\[Pi]}]&,Joe]//Timing
Out[274]=
{0.116667 Second,0}
You wrote
>Hey,
>
> I have a thing about Mathematica. Sometimes I have a real long
>expression that involves the integral of the sum of lots of cosines and
>sines of some variable let's say 't'. But having done some fancy maths
>on my own to reduce it and get into a simple integral from 0 to 2 Pi,
>and the sines and cosines all involve some integer multiple of t, the
>integration takes for ever, it basically hangs. Now, although the
>expression is long, and there are a lot of terms in it, it still just
>becomes a simple periodic integral from zero to 2 pi, and all the
>trigonometric terms involving t should just drop out. Kind of like what
>sometimes can happen if you are playing around with a Fourier series
>expansion (by the way, does Mathematica have a built in Fourier Series
>expansion? I mean something like Series[], but returns fourier
>coefficients?). Uptill now, I have been able to get by with something
>like using
>
>periodicIntegral={Cos[t] -> 0, Cos[2 t] -> 0, Cos[3 t] -> 0, Cos[4 t] ->
>0, Cos[5t] -> 0, Cos[6 t] -> 0, Cos[7 t] -> 0, Sin[t] -> 0, Sin[2 t] ->
>0, Sin[3 t] -> 0, Sin[4 t] -> 0, Sin[5t] -> 0, Sin[6 t] -> 0, Sin[7 t]
>-> 0};
>
>and then doing a replace on the expresion, multiplying the result by 2
>Pi. But now I am in a bind where no amount of TrigReduce, TrigExpand,
>TrigFactor, etc. will get this big ass expression into the desired form
>where the above is approriate (because there are other sines and cosines
>of other variables that get put into the terms and stand by
>themselves). Still, the expression should be easy to do for the
>computer, even I can go through and set these terms to zero, but it will
>just take me a long time. An example of what I am talking about, just
>try the following:
>
>In[687]:=
>Joe = a c Cos[t]/(g s) + b q Cos[2 t]/(c f) + c Cos[3 t]/(d a) +
> d f Cos[4 t]/(h a n) + e q Cos[5t]/(g a) + f l Cos[6 t]/(w r m) +
> g b Cos[7 t]/(o n x) + h Sin[t]/(b c) + i Sin[2 t]/(h e r) +
> j y Sin[3 t]/(l p) + d k Sin[4 t]/(j c) + l m a Sin[5 t]/(f s b h)
>+
> m p Sin[6 t]/(k j) + q n Sin[7 t]/(x c);
>
>In[688]:=
>Integrate[Joe, {t, 0, 2 Pi}]
>
>and you willl see it takes a long time to integrate. (It will
>eventually get done.) I know this is just zero, but why does it take so
>long for the computer to figure out? It is true that my expression is
>even longer than this one, so essentially it hangs, but basically it is
>the same problem. I do not what to be hunting through my equation from
>hell setting all the relevant trigonometric terms to zero when the
>computer should be able to do this. Well, sorry for the harangue but I
>greatly appreciate you reading down so far, really. If you have any
>suggestions or comments, point out I am an idiot there is some simple
>thing in Mathematica, please send it.
>
>Joe
--
Richard Gass
Department of Physics
University of Cincinnati
Cincinnati, OH 45221
phone- 513-556-0519
E-Mail gass at physics.uc.edu
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