MathGroup Archive 2002

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Headless set of elements?


JT, 

Here is one way:

mylists={list1,list2,list3,list4}

In[13]:=myfunc[Sequence @@ mylists]

Out[13]=myfunc[list1, list2, list3, list4]

where myfunc could be any function 

Cheers,

Brian




"JT Shen" <jushen1 at hotmail.com> wrote in message news:<a2ttev$eba$1 at smc.vnet.net>...
> Hi, I'd like to ask for help on the function of MultipleListPlot.
> 
> I am trying to use MultipleListPlot, and my dataset looks like
> 
> {list1, list2, list3, list4, ..., listn}, where the number of lists can 
> vary. However, the syntax of MultipleListPlot is as
> MultipleListPlot[list1, list2, list3, ..., listn]. In this case, what would 
> be the most efficient way to achieve this (instead of cut and past each list 
> by hand)?
> 
> Thanks for your help.
> 
> JT
> 
> 
> _________________________________________________________________
> MSN Photos is the easiest way to share and print your photos: 
> http://photos.msn.com/support/worldwide.aspx


  • Prev by Date: Re: ReplaceAll doesn't replace
  • Next by Date: Re: Headless set of elements?
  • Previous by thread: Re: Headless set of elements?
  • Next by thread: Re: Headless set of elements?