|
[Date Index]
[Thread Index]
[Author Index]
RE: Re: PDE
- To: mathgroup at smc.vnet.net
- Subject: [mg35328] RE: [mg35297] Re: PDE
- From: "DrBob" <majort at cox-internet.com>
- Date: Mon, 8 Jul 2002 03:19:56 -0400 (EDT)
- Reply-to: <drbob at bigfoot.com>
- Sender: owner-wri-mathgroup at wolfram.com
The sign of your eigenvalues is wrong:
f = Sin[k x]*Sin[m y];
D[f, x, x] + D[f, y, y] // Factor
(-(k^2 + m^2))*Sin[k*x]*Sin[m*y]
Bobby
-----Original Message-----
From: Jens-Peer Kuska [mailto:kuska at informatik.uni-leipzig.de]
To: mathgroup at smc.vnet.net
Subject: [mg35328] [mg35297] Re: PDE
Hi,
no but ist is easy by hand -- use the eigenfunctions
Sin[k Pi x/L]*Sin[m Pi y/L]
and the eigenvalues
k^2 Pi^2/L^2 + m^2 Pi^2/L^2
and use the Fourier series. That's the simplest example
in standard text books about PDE's. You don't need a
computer algebra
for that.
Regards
Jens
mitja Lakner wrote:
>
> Is there any package for solving eigenvalue problem for the Laplacian
operator
> on the 2D (not rectangular) region with zero boundary value?
>
> f_{xx}+f_{yy}= t f
>
> Mitja Lakner
Prev by Date:
Re: Integrate and warning messages.
Next by Date:
Inherited Cell Option Values
Previous by thread:
Re: PDE
Next by thread:
Re: PDE
|