Re: Integrate and warning messages.
- To: mathgroup at smc.vnet.net
- Subject: [mg35304] Re: [mg35295] Integrate and warning messages.
- From: Andrzej Kozlowski <andrzej at platon.c.u-tokyo.ac.jp>
- Date: Mon, 8 Jul 2002 03:15:31 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Take your equation and to see things better replace Sqrt[1+3x^2] by a symbols, say a: In[5]:= -Sqrt[1+3x^2]/(1+Sqrt[1+3x^2]) + Log[Exp[Sqrt[1+3x^2]]] - Sqrt[1+3x^2]Log[Exp[Sqrt[1+3x^2]]]/(1+Sqrt[ 1+3x^2]) == 0/.Sqrt[1+3x^2]->a Out[5]= -(a/(1 + a)) + Log[E^a] - (a*Log[E^a])/(1 + a) == 0 In[6]:= FullSimplify[%] Out[6]= (-a + Log[E^a])/(1 + a) == 0 This reduces to Log[E^a]==a. This equation holds in a part of the complex plane (including the real line) and is not valid elsewhere (e.g. for a = 2Pi I). Not surprisingly Mathematica cannot combine this information with the rest of your equations. Andrzej Kozlowski Toyama International University JAPAN http://platon.c.u-tokyo.ac.jp/andrzej/ On Saturday, July 6, 2002, at 06:46 PM, Andrea wrote: > Hi, > I'm trying to solve an integral and before getting the result > Mathematica warns me several times with this message: > > Solve::incnst: Inconsistent or redundant transcendental equation. > > After reduction, the bad equation is -Sqrt[1+3x^2]/(1+Sqrt[1+3x^2]) + > Log[Exp[Sqrt[1+3x^2]]] - Sqrt[1+3x^2]Log[Exp[Sqrt[1+3x^2]]]/(1+Sqrt[ > 1+3x^2]) == 0 > > > Can anyone explain it to me?? > > Thanks in advance, > Andrea. > > >