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MathGroup Archive 2002

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Re: Plotting problem

  • To: mathgroup at smc.vnet.net
  • Subject: [mg35338] Re: Plotting problem
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Tue, 9 Jul 2002 06:47:45 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <agbflh$jeo$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

what did you expect ?

(-1 + x) (-2 + 3 x)=(3 x^2 - 5 x + 2)

and the denominator 

(3 x^2 - 5 x + 2)/(x - 1)

canel.

Regards
  Jens


Steven Hodgen wrote:
> 
> Hello,
> 
> I'm a total Mathematica newbie, and I'm trying to get it to plot a simple
> rational eq. in such a way that it indicates where missing points are.
> Since I'm not sure how you'd prefer the eq. expressed, I've typed in in the
> parents so there can be no question of where the denominator is, as well as
> a cell expression.
> 
> (3 x^2 - 5 x + 2)/(x - 1)
> 
> Cell[BoxData[
>     FractionBox[
>       RowBox[{
>         RowBox[{"3",
>           SuperscriptBox["x", "2"]}], "-",
>         RowBox[{"5", "x"}], "+", "2"}],
>       RowBox[{"x", "-", "1"}]]], "Input"]
> 
> When I Plot[], this is just draws a straight line.  There is no indication
> where the hole is. How can I get this "fully correct" graph?
> 
> Thanks
> --Steven


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