Re: AW: Q: Simplify with "much less" assumptions

• To: mathgroup at smc.vnet.net
• Subject: [mg35644] Re: AW: Q: Simplify with "much less" assumptions
• From: phbrf at t-online.de (Peter Breitfeld)
• Date: Wed, 24 Jul 2002 02:06:08 -0400 (EDT)
• References: <ahivod\$gn6\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```Matthias.Bode at oppenheim.de schrieb:
>
> Hello Heather,
>
> try:
>
> 1 + x^2 /. {x -> 0}
>
> It will give you the 1 you wish.
>
> Best regards,
> Matthias Bode.
>
If you only want to neglect powers with exponent greater 1 you may use
the rule

In[1]:=regel=x^(n_/;n>1)->0

then

In[2]:=1 + x + x^2 + x^3 + x^1.5 + x^(7/4) + x^0.5 + x^(3/4)/.regel
Out[2]=1+x+x^0.5+x^(3/4)

Gruß Peter
--
=--=--=--=--=--=--=--=--=--=--=--=--=--= http://home.t-online.de/home/phbrf
Peter Breitfeld, Bad Saulgau, Germany   Meinen GnuPG/PGP-5x Key gibts dort

```

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