RE: RE: Question about Replace
- To: mathgroup at smc.vnet.net
- Subject: [mg35713] RE: [mg35696] RE: [mg35670] Question about Replace
- From: "DrBob" <majort at cox-internet.com>
- Date: Sat, 27 Jul 2002 06:43:14 -0400 (EDT)
- Reply-to: <drbob at bigfoot.com>
- Sender: owner-wri-mathgroup at wolfram.com
Actually, she wants a change of variables: expr/.x->z-y/.z->x. -----Original Message----- From: David Park [mailto:djmp at earthlink.net] To: mathgroup at smc.vnet.net Subject: [mg35713] [mg35696] RE: [mg35670] Question about Replace Heather, It works. x + y + z/(x + y) + e^(x + y) + w*x + y /. x + y -> x e^x + x + w*x + 2*y + z/x Since you wrote w*x + y and not w*(x+y) Mathematica simplified to obtain x + 2y so there is no replacement there. But generally you will have to use ReplaceRepeated (//.). x + y + z/(x + y) + e^(x + y) + w*(x + y) //. x + y -> x e^x + x + w*x + z/x David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ From: Xuguang Zhang [mailto:xzhang2 at is2.dal.ca] To: mathgroup at smc.vnet.net Hello All, I have an expression: x+y+z/(x+y)+e^(x+y)+w*x+y.... I want to replace any (x+y) term by x no matter how the expression looks like. I tried "/."command. However, it does not work properly. Is there any simple way of doing this? Thanks. -- Xuguang(Heather) Zhang