Re: PolynomialQ ?

*To*: mathgroup at smc.vnet.net*Subject*: [mg34911] Re: PolynomialQ ?*From*: lalu_bhatt at yahoo.com (Bhuvanesh)*Date*: Wed, 12 Jun 2002 02:16:00 -0400 (EDT)*References*: <ae4en8$9bc$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

"Juan" <erfa11 at hotmail.com> wrote: > Hi,I tried to check is a polynomial have a variable, ussing the function > PolynomialQ. > > In[1]:=p = x^3 - 2*x^2 + x - 1; > In[2]:=PolynomialQ[p, x] > Out[2]=True > In[3]:=PolynomialQ[p, y] > Out[3]=True > In[4]:=PolynomialQ[p, z^2] > Out[4]=True > In[5]:=PolynomialQ[p, {u, v}] > Out[5]=True > > What is the thing I am doing wrong? The polynomial in x is a constant in y, in z^2, and in {u,v}, and is therefore a polynomial in those variables as well. If you want no other variables to be present, you might look into FreeQ: http://documents.wolfram.com/v4/RefGuide/FreeQ.html -- Bhuvanesh, Wolfram Research.