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MathGroup Archive 2002

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Re: Assigning to a sublist

  • To: mathgroup at smc.vnet.net
  • Subject: [mg35173] Re: Assigning to a sublist
  • From: Peter Pein <petsie at arcor.de>
  • Date: Fri, 28 Jun 2002 02:31:03 -0400 (EDT)
  • Organization: Arcor
  • References: <afe4lv$h2h$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi Bob,
I didn't participate in writing the Mathematica-kernel, but I think it has z[[3]] as a 
temporary, unnamed reference, when trying z[[3]][[2]]=sth.

It works fine, if you type:

In[2]:=
zz[[3,2]] = Append[zz[[3,2]], {1, 1, 1, 1, 1}]
Out[2]=
{{2, 1}, {1, 1, 1, 1, 1}}
In[3]:=
zz
Out[3]=
{{2, {{1, 1}}}, {10, {{3, 1}}}, {5, {{2, 1}, {1, 1, 1, 1, 1}}}}

Peter


Bob Harris wrote:
> Howdy,
> 
> I'm trying to assign a new value to an entry in a sublist (of another list),
> and I can't understand why it won't work.
> 
> For example, I do the following:
> 
>   In[1]:= zz = {{2, {{1, 1}}}, {10, {{3, 1}}}, {5, {{2, 1}}}}
>   Out[1]= {{2, {{1, 1}}}, {10, {{3, 1}}}, {5, {{2, 1}}}}
> 
>   In[2]:= zz[[3]][[2]]
>   Out[2]= {{2, 1}}
> 
>   In[3]:= Append[zz[[3]][[2]], {1, 1, 1, 1, 1}]
>   Out[3]= {{2, 1}, {1, 1, 1, 1, 1}}
> 
>   In[4]:= zz[[3]][[2]] = Append[zz[[3]][[2]], {1, 1, 1, 1, 1}]
>   Set::"setps : zz[[3]] in assignment of part is not a symbol."
>   Out[4]= {{2, 1}, {1, 1, 1, 1, 1}}
<snip>
> 
> Thanks,
> Bob H
> 
> 





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