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Re: Limit with restrictions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg34309] Re: [mg34269] Limit with restrictions
  • From: Vladimir Bondarenko <vvb at mail.strace.net>
  • Date: Tue, 14 May 2002 04:12:30 -0400 (EDT)
  • Reply-to: Vladimir Bondarenko <vvb at mail.strace.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Dear Hannes,

What I had using the Calculus`Limit` package was


   p = m^(-1 + a + b + n)*(a/(a + b + n))^a*((b + n)/
      (a + b + n))^(b + n)*(a + b + n);

   restrictions = {a > 0, b > 0, n > 0, a + b + n < 1};

   << Calculus`Limit`

   Simplify[Limit[p, m -> Infinity],restrictions]

   0


My warning is: Please do check the answer carefully using
the (algebraic, geometric etc) context of your problem,
the common sense, at least ;-)

Calculus`Limit` tends to generate wrong answers.


Regards,

Vladimir Bondarenko




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