Re: A question about Mathematica
- To: mathgroup at smc.vnet.net
- Subject: [mg34613] Re: [mg34559] A question about Mathematica
- From: Andrzej Kozlowski <andrzej at platon.c.u-tokyo.ac.jp>
- Date: Wed, 29 May 2002 02:46:53 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
What you have written does not make much sense. You should really post your real problem. However, one can speculate that wthe problem you are having is caused by too low precision in your computations. For example, here is an example which looks similar to yours: In[43]:= A=(1.`1)^10;B=2; In[45]:= A/Aâ?¥B/B Out[45]= False Depending on the nature of your problem changing to fixed precision arithmetic may be the answer (this seems to be your friends suggestion). But this can't be known until you post your problem. Andrzej Kozlowski Toyama International University JAPAN http://platon.c.u-tokyo.ac.jp/andrzej/ On Monday, May 27, 2002, at 02:17 PM, Chen-Ying Huang wrote: > Hi, > > I have a question about Mathematica and yet I couldn't find an answer > to. Could you please consider giving me a help on this? This is not a > long question and I hope it won't bother you too much. > > I was doing some computations. A computation gives me something like > A/A, another computation gives me something like B/B. I then do a > true-false statement, that is, If [A/A>=B/B, 1, 0]. Since both > computations (A/A and B/B) equal to one, the statement is true and hence > the If statement should lend a 1 as specified. > > However, I found out that the If statement lends a zero because > somehow, in the computations, A/A is less than B/B by the order of 10 to > the power of -16. > > Some friends told me that it must be because the bytes used by the > computations A/A and B/B are different, so to correct this problem, I > should assign the maximum byte to each object. > > Since I am not very familiar with Mathematica, after an afternoon's > search, I still have no clue about how to do that. > > Could anyone give me a help on this? I really appreciate it. > > ChenYing Huang > > > >