RE: Specifying fill color for a bounded 2D region
- To: mathgroup at smc.vnet.net
- Subject: [mg37826] RE: [mg37782] Specifying fill color for a bounded 2D region
- From: "David Park" <djmp at earthlink.net>
- Date: Thu, 14 Nov 2002 06:11:32 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Steven,
Use the Fills option.
Needs["Graphics`InequalityGraphics`"]
Needs["Graphics`Colors`"]
InequalityPlot[Xor[(x + 1/2)^2 + y^2 <= 1,
(x - 1/2)^2 + y^2 <= 1], {x}, {y},
Fills -> {DeepSkyBlue, DeepNaplesYellow}];
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
From: Steven T. Hatton [mailto:hattons at globalsymmetry.com]
To: mathgroup at smc.vnet.net
This is a long-standing issue for me. I would like to be able to specify a
particular bound region of a graph and determine what collor to fill the
region with. The InequalityGraphics does almost what I want. If I could
specify the color with which to fill each region of the graph produced by
code such as this example from the help browser I would have my solution:
\!\(\(InequalityPlot[\
Xor[\ \((x + 1\/2)\)\^2 + \ y\^2 <= 1, \ \((x - 1\/2)\)\^2 + \ y\^2 <=
1], \ {x}, \ {y}\ ];\)\)
This seems like it should be a no-brainer, but I have yet to find a solution
to this. Does anybody know of a way to accomplish such a thing? All I want
to do is produce a Ven diagram using the traditional circles found in
textbooks, and fill the different regions with unique colors.
--
STH
Hatton's Law:
"There is only One inviolable Law."