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Re: Peculiar output from DSolve

It isn't so. C[1] is an arbitrary (smooth) function. After all, what 
you have got is a partial differential equation. For example, you can 
take C[1] to be Sin:

v[x_, y_] = u[x, y] /. DSolve[y*D[u[x, y], x] ==
       x*D[u[x, y], y], u[x, y], {x, y}] /. C[1] -> Sin

{Sin[(1/2)*(x^2 + y^2)]}

y*D[v[x, y], x] == x*D[v[x, y], y]


Andrzej Kozlowski
Yokohama, Japan

On Friday, October 4, 2002, at 06:01 PM, Selwyn Hollis wrote:

> In:  DSolve[y*D[u[x, y],x] == x*D[u[x, y],y], u[x,y], {x, y}]
> Out:  {{u[x, y] -> C[1][(1/2)*(x^2 + y^2)]}}
> Square brackets are used as grouping symbols in the result!??  :^O
> Somebody say it isn't so.
> ---
> Selwyn Hollis

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