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Re: PatternMatching with Dt[]


Try using...

Dt[x]/.HoldPattern[Dt[arg_]]->f[arg]


"Johannes Ludsteck" <johannes.ludsteck at wiwi.uni-regensburg.de> wrote in message news:<ap0753$c3m$1 at smc.vnet.net>...
> I would like to replace Dt[x_] in a complex 
> expression. For example consider
> 
> Dt[x]/.Dt[arg_]->f[arg]
> 
> where x is a pure Symbol (has no value).
> However, Mathematica refuses apply the rule.
> Various other attempts, for example 
> Unevaluted[Dt[arg_]]:>f[arg]
> and HoldForm[...] were unsuccessful.
> 
> I managed to  circumvent the problem by
> Dt[x]/.Dt->fun
> However, I were more happy if I understood why the 
> first attempt was not successful.
> Can someone explain?
> 
> Best regards,
> 	Johannes Ludsteck
> <><><><><><><><><><><><>
> Johannes Ludsteck
> Economics Department
> University of Regensburg
> Universitaetsstrasse 31
> 93053 Regensburg
> Phone +49/0941/943-2741


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