AW: nth roots

*To*: mathgroup at smc.vnet.net*Subject*: [mg36610] AW: [mg36581] nth roots*From*: Matthias.Bode at oppenheim.de*Date*: Fri, 13 Sep 2002 23:33:08 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Hello watcher2, try: (((((3^(1/2))^(1/2))^(1/2))^(1/2))^(1/2))/(6^(1/2)) Out: 1/(Sqrt[2]*3^(15/32)) You can see what happened: 1st: 6^(1/2) = 2^(1/2)*3^(1/2); 2nd: subtraction of the 3's exponents (1/2)^5 - 1/2 = 1/32 - 16/32 = - 15/32. MATHEMATICA does these straightforward simplifications without you having to invoke Simplify[]. Best regards, Matthias Bode Sal. Oppenheim jr. & Cie. KGaA Koenigsberger Strasse 29 D-60487 Frankfurt am Main GERMANY Tel.: +49(0)69 71 34 53 80 Mobile: +49(0)172 6 74 95 77 Fax: +49(0)69 71 34 95 380 E-mail: matthias.bode at oppenheim.de Internet: http://www.oppenheim.de -----UrsprÃ¼ngliche Nachricht----- Von: watcher2 at sympatico.ca [mailto:watcher2 at sympatico.ca] Gesendet: Freitag, 13. September 2002 07:14 An: mathgroup at smc.vnet.net Betreff: [mg36581] nth roots Simplify: 5nth sqrt (3)/sqrt (6) 5nth Sqrt(3) ------------ Sqrt(6) 1st.. is this the correct notation for use on a computer 2nd.. how is the solution solved, step by step please.