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Re: Different letters different solutions!!

Neither of your solutions are "wrong" according to your rules.

Lets step through them

In[3]:=integrate[f Exp[-0.8316*tau], t]

The function Times is Orderless, so the kernel rewrites the integrand in
lexographical (sp) order as

In[3]:=integrate[Exp[-0.8316*tau] f, t]

It then applies rule 1:

integrate[c_ y_,t_]:=c*integrate[y,t]/;FreeQ[c,t]

Well,  The term "Exp[-0.8316*tau]" contains no "t", so according to your
rule it is equal to

Exp[-0.8316*tau] integrate[f, t]

At this point none of your rules apply, so the kernel stops.

When you use "a" instead of "f" the ordering of the "constant" and the
exponential are reversed, and you get the behaviour that you actually
desired.  A simple fix is to replace the condition in rule 1 by


You may however want to think carefully about exactly what you want your
function "integrate" to do.  For example, with the rules given, the
variable "t" and the variable "tau" seem to be playing the same role.


On Thu, 19 Sep 2002 guillerm at wrote:

> I have defined two functions (Math 4.1)
> In[1]:= integrate[c_ y_,t_]:=c*integrate[y,t]/;FreeQ[c,t];
> In[2]:= integrate[Exp[(a_.)*tau], t_]:=(E^(a*t)-1)/a/;
>         FreeQ[a,t]&&FreeQ[a,tau];
> when I applied these functions the solution is different if the coefficient is
> the letter d or lower (solution fine) or f or higher (solution wrong) . Here is
> an example:
> Using letter f
> In[3]:=integrate[f Exp[-0.8316*tau], t]
> Out[3]:=integrate[f, t]/E^(0.8316*tau) (*wrong*)
> Using letter a (the solution is rigth
> In[4]:=integrate[a Exp[-0.8316*tau], t]
> Out[4]:=-1.20250*a*(-1 + E^(-0.8316*t))
> What it wrong?
> Guillermo
> Sanchez
> ---------------------------------------------
> This message was sent using Endymion MailMan.

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