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MathGroup Archive 2002

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How to Properly Use Partition?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg36737] How to Properly Use Partition?
  • From: "Dana DeLouis" <delouis at bellsouth.net>
  • Date: Sat, 21 Sep 2002 02:22:06 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

I believe this will work.  The {1,1} uses overhang at the end, and the 0
is the character to use.

P = {"1", "1", "1", "1", "0", "1", "0", "1"}


Reverse[Partition[p, 3, 3, {1, 1}, 0]]

{{"0", "1", 0}, {"1", "0", "1"}, {"1", "1", "1"}}


-- 
Dana DeLouis 
Windows XP
$VersionNumber -> 4.2
= = = = = = = = = = = = = = = = = 


"flip" <flip_alpha at safebunch.com> wrote in message
news:amem4s$41p$1 at smc.vnet.net...
> b = 2; r = 4;
> n = "10101111"
> p = Reverse[Characters[n]]
> {"1", "1", "1", "1", "0", "1", "0", "1"}
> z = Reverse[Partition[p, r]]
> {{"0", "1", "0", "1"}, {"1", "1", "1", "1"}}  (* this is okay *)
> b = 2; r = 3;
> z = Reverse[Partition[p, r]]
> {{"1", "0", "1"}, {"1", "1", "1"}}  (* this is wrong, want output to
be
> {{0,1,0},{1,0,1},{1,1,1}}*)
> 
> What I want is a function that takes a string as input, parses each
> character, partitions that to whatever length I want and Prepends
zeros to
> the input as needed to create an appropriate length array.
> 
> What is the correct syntax for Partition (or is there a better way?).
> 
> Thanks, Flip
> 
> Remove _alpha to email.



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