Re: Super-Increasing List
- To: mathgroup at smc.vnet.net
- Subject: [mg40469] Re: Super-Increasing List
- From: atelesforos at hotmail.com (Orestis Vantzos)
- Date: Mon, 7 Apr 2003 04:53:44 -0400 (EDT)
- References: <b6m04c$efg$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
OrestisSuperIncreasingQ[lst_] := OrderedQ[lst] &&
Module[{sum = 0},
If[Scan[If[# <= sum, Return[False], sum += #] &, lst] ===
Null, True,
False]];
The advantage of this function is that it stops checking as long as an
element does not satisfy the super-increasing condition.
Orestis
"flip" <flip_alpha at safebunch.com> wrote in message news:<b6m04c$efg$1 at smc.vnet.net>...
> Hello,
>
> does a command or module exist which can test a list of values and determine
> if it is a super-increasing list?
>
> A super-increasing list satifies the conditions:
>
> a. the list is in increasing order
> b. each element of the list is greater than the sum of it's previous
> elements
>
> Example:
>
> list = {2, 3, 7, 15, 31}
>
> So check:
>
> a. It is in increasing order and
> b. 3 > 2, 7 > 3+ 2, 15 > 7 + 3 + 2 and 31 > 15 + 7 + 3 + 2,
>
> hence the list is super-increasing.
>
> Thanks for any inputs, Flip
>
> To email me, remove "_alpha".
- Follow-Ups:
- Re: Re: Super-Increasing List
- From: Dr Bob <majort@cox-internet.com>
- Re: Re: Super-Increasing List