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Re: How to get Mathematica to actually *add* fractions?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40540] Re: [mg40529] How to get Mathematica to actually *add* fractions?
  • From: Dr Bob <majort at cox-internet.com>
  • Date: Wed, 9 Apr 2003 20:26:38 -0400 (EDT)
  • References: <200304090533.BAA08384@smc.vnet.net>
  • Reply-to: majort at cox-internet.com
  • Sender: owner-wri-mathgroup at wolfram.com

(2/(3x)) + (6/x) + (x/(x + 3)) // Together

(60 + 20*x + 3*x^2)/ (3*x*(3 + x))

Bobby

On Wed, 9 Apr 2003 01:33:41 -0400 (EDT), cdj <a_cjones at hotmail.com> wrote:

> Hi,
>
> Like the subject says, but take for example:
>
> (2/(3x)) + (6/x) + (x/(x + 3))
>
> Sending to the kernel simply gives:
>
> 20/3x + x/(3+x)
>
> What I wanted/hoped for was the common-denominator version:
>
> (3x^2 + 20x + 60)/(3x(x+3))
>
> Is there any way to get Mathematica to give the one-denominator
> version of sums of fractions?
>
> thanks,
>
> cdj
>
>



-- 
majort at cox-internet.com
Bobby R. Treat



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