Re: Newbie Question: Solving for x?
- To: mathgroup at smc.vnet.net
- Subject: [mg40699] Re: Newbie Question: Solving for x?
- From: bobhanlon at aol.com (Bob Hanlon)
- Date: Mon, 14 Apr 2003 04:01:27 -0400 (EDT)
- References: <b7avu5$qpi$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Clear[x,y];
Solve[y == E^(-x^2/2)/Sqrt[2*Pi], x]
{{x -> (-I)*Sqrt[2]*Sqrt[Log[Sqrt[2*Pi]*y]]},
{x -> I*Sqrt[2]*Sqrt[Log[Sqrt[2*Pi]*y]]}}
Bob Hanlon
In article <b7avu5$qpi$1 at smc.vnet.net>, "AngleWyrm"
<no_spam_anglewyrm at hotmail.com> wrote:
<< Subject: Newbie Question: Solving for x?
From: "AngleWyrm" <no_spam_anglewyrm at hotmail.com>
To: mathgroup at smc.vnet.net
Date: Sun, 13 Apr 2003 06:26:13 +0000 (UTC)
I have a formula expressing y in terms of x:
\!\(y = \[ExponentialE]\^\(\(-x\^2\)\/2\)\/\@\(2 \[Pi]\)\)
How do you make it so that it expresses x in terms of y? >><BR><BR>