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Re: Simplification of definite integral?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40720] Re: Simplification of definite integral?
  • From: "Dr. Wolfgang Hintze" <weh at snafu.de>
  • Date: Tue, 15 Apr 2003 03:56:58 -0400 (EDT)
  • References: <b7dq8s$6a2$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Andrzej,

thanks for your hint. The final answer is what I expected from 
mathematica (and know to be correct).

Best regards,
Wolfgang


Andrzej Kozlowski wrote:

> Mathematica has difficulties dealing with the (apparent) singularities 
> at x==d and x == -d so if you try straight forward Integrate it want's 
> you to assume that d non-real. However, you can get an answer probably 
> closer to what you desire by setting the PrincipalValue option to True:
> 
> 
> Integrate[Sin[x-d]/(
>    x-d) Sin[x+d]/(x+
>        d),{x,-Infinity,Infinity},PrincipalValue->True,Assumptions->{d>0}]
> 
> 
> (Pi*Cos[d]*Sin[d])/d
> 
> For example for d =1 we get:
> 
> 
> %/.d->1.
> 
> 
> 1.42832
> 
> This is probably right, particularly that
> 
> 
> NIntegrate[(Sin[x - 1]/(x - 1))*(Sin[x + 1]/(x + 1)),
>    {x, -Infinity, 1, Infinity}]
> 
> 
> NIntegrate::slwcon:Numerical integration converging too slowly; suspect 
> one \
> of the following: singularity, value of the integration being 0, 
> oscillatory \
> integrand, or insufficient WorkingPrecision. If your integrand is 
> oscillatory \
> try using the option Method->Oscillatory in NIntegrate.
> 
> 
> NIntegrate::ncvb:NIntegrate failed to converge to prescribed accuracy 
> after 7 \
> recursive bisections in x near x = 187.1757811919331`.
> 
> 
> 1.4283406894658994
> 
> 
> Andrzej Kozlowski
> Yokohama, Japan
> http://www.mimuw.edu.pl/~akoz/
> http://platon.c.u-tokyo.ac.jp/andrzej/
> 
> 
> 
> 
> 
> On Sunday, April 13, 2003, at 03:17  pm, Dr. Wolfgang Hintze wrote:
> 
> 
>>How do I get a satisfactory result from mathematica for this function
>>
>>f[d]:=Integrate[Sin[x-d]/(x-d) Sin[x+d]/(x+d),{x,-Infinity,Infinity}]
>>
>>I tried
>>
>>f[d]//ComplexExpand
>>
>>and several assumptions but I didn't succeed. Any hints?
>>
>>Wolfgang
>>
>>
>>
>>
>>
> 
> 



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